1. If there are 10 people in a room and they would make handshakes with each one in the room, how many unique handshakes would be made?
find:
H = number of unique handshakes
solution:
n = number of people = 10
H = (n - 1) + (n - 2) + (n - 3) .....until LAST ADDEND is 1
first term = PEOPLE - 1
H = 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1
H = 45
if there are only 5 people in the room
H = 4 + 3 + 2 + 1
H = 10
2. If a dice and a coin are tossed, what is the probability that you will get a 4 on the dice and heads on the coin?
solution:
P = Pdice * Pcoin
P = 1/6 * 1/2
P = 1/12
3. A circular spinner is marked W, X, Y, Z. what is the probability of NOT getting an X if spinned thrice?
solution:
if spinned once ---> P1 = 3/4
if spinned twice ---> P2 = 3/4 * 3/4 = 9/16
if spinned thrice ---> P1 = 3/4 * 3/4 * 3/4 = 27/64
4. There are 5 choices each question. What is the probability of correctly guessing 3 questions?
solution:
P = 1/5 * 1/5 * 1/5
P = 1/125
5. If you have 5 pants and 8 shirts, how many ways can you wear them?
solution:
W = 5 * 8
W = 40
6. In a restaurant, there are 3 choices of soup, 5 choices of entrees, and 2 choices of desert. How many ways can you order them if each order consists of one soup, one entree, and one desert?
solution:
W = 3 * 5 * 2
w = 30
7. If 4 warriors line up so that the order matters, how many ordered combinations (permutations) are possible?
P = 4 * 3 * 2 * 1
P = 24
8. If you count from 1 to 100, How many zeroes are there? How many sevens are there?
solution:
let
Zt = total number of 0's
St = total number of 7's
1 to 10 : z = 1, s = 1
11 to 20: z = 1, s = 1
21 to 30: z = 1, s = 1
31 to 40: z = 1, s = 1
41 to 50: z = 1, s = 1
51 to 60: z = 1, s = 1
61 to 70: z = 1, s = 2 (67, 70)
71 to 80: z = 1, s = 10 ( 71, 72, 73, 74, 75, 76, 77, 78, 79 ---> there are two 7's on 77 )
81 to 90: z = 1, s = 1
91 to 100: z = 2, s = 1 ( 100 ---> two zeroes on 100 )
Zt = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 2 = 11
St = 1 + 1 + 1 + 1 + 1 + 1 + 2 + 10 + 1 + 1 = 20
do you have more?
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